Production Management:
Given the following table, forecast for the production of shirt using least square method for 2019, 2020, and 2021.Show your soluction.
| YEAR | PRODUCTION |
| 2012 | 343.5 PIECES |
| 2013 | 381.2 PIECES |
| 2014 | 437.5 PIECES |
| 2015 | 323.6 PIECES |
| 2016 | 231.4 PIECES |
| 2017 | 443.5 PIECES |
| 2018 | 525.2 PIECES |
Here response y = Production
and x = (year - origin) / Interval
year 2015 is the origin as it is in the middle
Constructing the table again with new column x we get,
| Year | Production (y) | x |
| 2012 | 343.5 PIECES | -3 |
| 2013 | 381.2 PIECES | -2 |
| 2014 | 437.5 PIECES | -1 |
| 2015 | 323.6 PIECES | 0 |
| 2016 | 231.4 PIECES | 1 |
| 2017 | 443.5 PIECES | 2 |
| 2018 | 525.2 PIECES | 3 |
Now creating the linear regression line between x and y we get,
and,
So the regression line becomes, yi = 383.7 + 16.557 xi
Now for year 2019, 2020 and 2021, x will be 4, 5 and 6 respectively.
Now for year 2019 (x = 4) the forecasted value of Production (y) will be,
Now for year 2020 (x = 5) the forecasted value of Production (y) will be,
Now for year 2021 (x = 6) the forecasted value of Production (y) will be,
**If your answer does not match please comment.
Production Management: Given the following table, forecast for the production of shirt using least square method...
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(USE ONLY
EXCEL SHEET FOR DATA, FORMULAS, and the
GRAPHS)
Ø For the following list of data
(number of sold cars in every year ) , apply “exponential smoothing
with trend” for all the years below. (i.e find the Forecast
including trend) (20%):
---- case1 use : α=
0.2 and β = 0.05
----
case2 use: for α=
0.05 and β = 0.2
Calculate MAD for both cases. Decide
which case values are better and why?
Assume trend is zero for
the 2012 years.
Year
Number of sold cars
2012
150...
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