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The displacement vectors A and B shown in the figure below both have magnitudes of 3.00 m. The direction of vector A is θ = 48 Find graphically 4. (a) A +B (b) A + 3 B (c) A -B 48
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Answer #1

A = -3i

B = -3cos48i - 3 sin 48j = -2i - 2.23j

(a) A+ B = -3i - 2i - 2.23j

= -5i - 2.23j

(b) A + 3B = -3i + 3(-2i - 2.23j)

= -9i - 6.68j

(c) A- B = -3i - (-2i - 2.23j)

= -i + 2.23j

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