Question

Home Work by 3.80 × 5. (a) Two protons in a molecule are separated 0 10 m. Find the-electric force exerted by one proton on e other, (b) How does the magnitude of this force com- pare to the magnitude of the gravitational force between the two protons? (c). What If? What must be the charge- to-mass ratio of a particle if the magnitude of the gravita- tional force between two of these particles equals the magnitude of electric force between them? Table 23.1 Charge and Mass of the Electron, Proton, and Neutron Particle Charge (C) Mass (kg) Electron (e) -L6021917X10-19 9.109 5 × 10-31 Proton (p) +1.602 191 7 x 10-19 1.67261 x 10- Neutron (n) 0 1.67492× 10-27 9 nlaced with

Answer 1

(a) Electric force is given by: F_e = 1/4 pi epsilon_0 times q_e q_e/r^2 equation (1) where q_e = charge of electron r = distance between the two electron = 9 times 10^9 Nm^2 C^-2 times (1.6 times 10^-19 C)^2/(10^-10 m)^2 = 2.3 times 10^-8 N Answer (b) Gravitation force exerted between the two protons is given by: F_g = G m_e m_e/r^2 equation (2) where G = gravitational constant m_e = mass of electron = 6.67 times 10^-11 Nm^2 kg^-2 times (9.1 times 10^-31 kg)^2/(10^-10 m)^2 = 5.523 times 10^-51 N Now, comparing Gravitational force & electrostatic force between the electrons: F_e/F_g = 2.3 times 10^-8 N/5.523 times 10^-51 N = 4.16 times 10^42 Thus, electric force is nearly 10^42 times the gravitational force between the electrons. Answer (c) Now, according to given condition: Electric force = Gravitational force \r\n 1/4 pi epsilon_0 times q_e q_e/r^2 = G times m_e m_e/r^2 (from equ(1)