In a certain geometry a proton does not get deflected while passing through a magnetic field region. Under what condition is this possible?
If the charged particle is moving along the magnetic field -- parallel or antiparallel to the magnetic field -- then there would be no force on it.
In a certain geometry a proton does not get deflected while passing through a magnetic field...
Figure1 of 1The figure shows a proton traveling to the right through a magnetic field B pointed into the page. Proton has a velocity of v. What electric field strength will allow the proton in (Figure 1) to pass through this region of space without being deflected? Assume that B = 0.010 T and v = 2.5×107 m/s. What is the electric field direction?
A proton with v = 450 m/s is moving through a region in which the magnetic field is B = 2.3 T. If the magnitude of the force on the proton is 6.9 10-17 N, what angle does the proton's velocity make with ? (Enter the smallest possible angle.)
15. Use the right-hand rule to determine the direction of the force on the charges moving in the magnetic fields below The force is The force is sores Force is The proton will be deflected Label the poles of the horseshoe magnet to reflect what is happening. 6. A beam of electrons passes through a magnetic field without being deflected. What can you conclude about the orientation of the beam relative to the magnetic field? Sketch a diagram showing the...
A proton moves in a region of uniform, constant magnetic field. The magnetic field points into the page and the proton is observed, at one moment, to be moving to the right (as shown). Which of the following pictures indicate a velocity that the proton might have at a later time? Explain why each is possible or not possible.
A proton travels through a region of uniform magnetic field at an angle θ relative to the magnetic field. The magnitude of the magnetic field in this region is 1.01 T, and the proton's velocity is 500,000 m/s when it experiences an acceleration whose magnitude is 1.27 x10^13. Calculate the angle θ.
A proton travels through a region of uniform magnetic field at an angle θ relative to the magnetic field. The magnitude of the magnetic field in this region is 0.991 T, and the proton's velocity is 500,000 m/s when it experiences an acceleration whose magnitude is 1.25×10 13 m/s2. Calculate the angle θ.
A proton enters a region of constant magnetic field, perpendicular to the field and after being accelerated from rest by an electric field through an electrical potential difference of 470 V. Determine the magnitude of the magnetic field, if the proton travels in a circular path with a radius of 22 cm. 1.42e-3 How can you determine the speed at which the proton enters the region of constant magnetic field? What force provides the centripetal force that causes the proton...
A beam of electrons passes through a magnetic field without being deflected. What can you conclude about the orientation of the beam relative to the magnetic field? (Ignore any other fields.)
A proton is passing the origin. The magnetic field at the (x,y,z) position ( 1 mm , 0 mm, 0 mm) is 1.0×10−13ȷ^T. The field at (0 mm, 1 mm , 0 mm) is −1.0×10−13ı^T. What is the speed of the proton?
A proton moves through a magnetic field at 39.7% of the speed of light. At a location where the field has a magnitude of 0.00629 T and the proton\'s velocity makes an angle of 141° with the field, what is the magnitude of the magnetic force acting on the proton?