Question

Tungsten trioxide (W0z) has a rich yellow color and is often used as a pigment in ceramics and paints. To test a ceramic vase for its Wo, content, a 10.13 g sample of the vase was ground and reduced with Pb(Hg) to convert any Wo, to W3+ The resulting W3+ was transferred to 500.0 mL of 1.00 M HCl. A 100.00 mL aliquot of the HCl solution required 13.75 mL of 0.09674 M potassium permanganate (KMnO2) to reach the purple endpoint. A blank required 0.25 mL. Balance the redox reaction. redox reaction: MnO2 + W3+ — Mn²+ + WO3+ Determine the percent Wo, in the ceramic sample. percent WOZ:

Answer 1

Given lido much = 500.0 mL 100.00 mL Aliquot of the Hel k mnoy = 0.09674 m solution required = 13,75 m2 A bank required 0.25 ml The redox reaction is Mno, tw3t > Mn2t + wort The balanced redox reaction is 5 w2143 M70, + 4H* _>5w0,94 3 M12*2 440 percent (103) = 22:14 volume hrane, required by aliquet = 13-75 m2 volume of kramoy vequired by blank = 0,25 mols 22.11%

Actual volume of kmoy required = (volume kmpo, sequired by aliquot) - (volume komunay required by blank] Actual volume of kmnoy required = 113.45 ml) - 10.25mL) = 13.5 ml il Actual volume of kmnou required = 13.5 mL Moles kmnon required = (concentration kmnoy) (volume kmnoy sequired liter) = 10.09674) (13.5x1031) = 1:30 x103 - rolex kono, seguired = 1300157

modes way in aliquot = (malog throne, cepures de cuina Moles wat in aliquot = (130x16-3)(3) = (130X16*3) (1.666) = 2.166x103 mol modes wat in aliquot + 2-165 x 102mol Total moks wat (moles watin aliquot ( Talal udbone l volume of aliquot -Total moles W3t = 12166x103) ( 300 M2) = (2.166X163) (5) = 0.01083 mol Total moles w37 = 0.01083 mol moles wo3 = Total moles wat moles wo3 = 0.01063 mol

mase Woz = 10.01083 mol) (molar mass woz) = (0.0108 3 mol) 1231.8382g/mol) :: mags nog = 2:51080 g mass percent uns = mange vee 0.2478 X 100 = 24.78% mass percent Woz = 24.78% z please rate me...
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