Question

14. (14 points) Tartaric acid, H2C4H406, (MW =150.087 g/mol) is a diprotic acid that is naturally abundant in grapes. In the process of winemaking, a titration is commonly done to determine the tartaric acid content in the grape juice. a. A particular sample of grape juice requires 40.00 mL of 0.2090 M KOH to completely neutralize the tartaric acid. What mass of tartaric acid was present? b. If the initial grape juice sample had a mass of 75.00 g, what is the weight percent of tartaric acid in the sample?

Answer 1

H₂ C4H206 + 2KOH → K2 C q + 6 + 2H2O I moe TARTARIC ALD NEUTRALIZES 2 mol KOH. NO. Of moles Of KOH = 0.2090 moe x 40.00ml * 0.001L Ime = 8.36x103 more 8.36x10 moe KOH REACTS WITH . = 8.36x10 mol x 1 = 4.18 x 10 moe __3 TARTARIL TAUP x MASS OF TARTARIC AUD = #moles , MN of TARTARIC AUD TARTARIC Alp = 4:18 x 10 mol x 150.081 9 - 10.62791 PERCENT TARTARIL AUD IN THE SAMPLE = 0.6279 x 100 = 75.000 - 10.8367.