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Use the References to access important values if needed for this question. The following information is given for manganese a
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Answer #1

Molar mass of Mn = 54.94 g/mol

mass(Mn)= 37.9 g

use:

number of mol of Mn,

n = mass of Mn/molar mass of Mn

=(37.9 g)/(54.94 g/mol)

= 0.6898 mol

For freezing heat is released

Now use:

Q = -Hfus * number of mol

= -14.6 kJ/mol * 0.6898 mol

= -10.07 KJ

Answer: -10.1 KJ

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