Question

A very long time after t=0, when all currents and voltages in the circuit have been settled down to steady values, the switch is opened again. What will be the current flowing through the 100-Ohm resistor 0.02 seconds after the switch is opened. Make sure that your specific in its direction (Up or Down)?

10 2 2 H 10 V 100 000 wW S

Answer 1

se los 3 loose 10u llele when all currents have settled down, inducto esters stedy stade and gets shost conceited. Io non 31oo VICO jov. Since 100 & is short circuited, 10 = 100 x 10 =YT107 = 1A 7 at t-o, switch is opened, circuit is dansa at Since inductor doeanot XI60) allow sudden change of & coor Zah cloorent, : I 60+) - IO) .. I (0)sin Inductor worent is gienoa, It= Int(Io) - In) e to T= 2 x t-aroo a to, entire energy stored in inductor would be dissipeded across sexistes, Ia= OA 1164): 0 (1-0) e-7

Itl+) = le-tit at t=0.025 I 64). e-002A100 Ilbf) = ė'' Inst) = 0.367 A at t=0.02s current is 0.367A and its direction is downwards.