Question

mgh

3. In this question you will do some algebra to determine two relations that you will need for Part 2 of this lab. Write down Eq. 11 twice. In the first statement, set the rotational kinetic energy term equal to zero (i.e. 1/2lo 0) -call this your "No Krot model". Leave the second as it is written in Eq. 11 call this your "Krot model". For both models, solve for v in terms of g, h, and a. In the Krot model, you will need to use / kmr2 (Eq. 3) and v/r. The solution for the Krot model will have a k term as well. Once you have solved for v, use the kinematic relation, v at, and solve for t for both models separately. These two solutions represent the predicted time it will take an object to descend a height, h, down an inclined plane when you assume all kinetic energy in the system is translational (No Krot model) and when you assume the kinetic energy is distributed between translational and rotational motion (Krot model)

Answer 1

migh = tmp?tt zw when II 02.0 mighthoz o=12gh at (8 gb t = 2gh No Krod model migh: I mo? & Į 7W? - = 1mo? + 1 km r²w² olmut Limary figh= l m 2 ² elk mo? 02 (1tk) = rgh r = 29h 7+R 2gb at = + K I knot model} I da 1/2gh a HR