Question

What total capacitances can you make by connecting a 4.12 µF and 7.72 µF capacitor together?

series	µF
parallel	µF

Answer 1

When these capacitor are connected in series then

$\frac{1}{C_s}= \frac{1}{C_1}+\frac{1}{C_2}$

$\frac{1}{C_s}= \frac{1}{4.12 \mu F}+\frac{1}{7.72 \mu F}$

$C_s= 2.69 \mu F$

When connected in parallel

$C_P= C_1+ C_2 = 4.12 \mu F + 7.72 \mu F\Rightarrow 11.84 \mu F$