Question

Liquid propane (C3H8) is a common heating fuel in rural Nevada where there is no access to a natural gas pipeline. An average home will use roughly 1000 gallons of liquid propane for heating during a year if this is the only source of heating. Given that a gallon is 3.79 liters and the density of liquid propane is 0.493g/cm3, how many grams of carbon dioxide are produced in the combustion of 1000 gallons of propane needed to heat a home? (Note: You can calculate this to 3 significant figures.)

Answer 1

C₃ Hy + 50, L Volume of → 360 + 4H₂O G Hg = 1000 gallons = toco gallons x 3.79 L - 1 gallory = 32.90 L 12 Loo Mass of C3 Hg = Volume x Density = 37904 X 0.4939 lom? = 3190LX Tooocm3 x0.443.916m3 las 1 - 10000) - = 1868470g I No of moles of C3 Hg = _Mass = 1808470 g Molar Mass 44.1 g/mol = 42368.9342 mol L 8 1 mole No of (3Hg gire males of (og 3 mole co produced = 32 423 68.9342 mol = 127, 106.803 mal 1. Mass of (Og produced = No of moles x Molar Mass = 127 106.803 mol x 44. of g/mol = 559 X 100g