Question

Problem 9:

A ball is thrown with a speed of 20 m/s at an angle of 37° above the horizontal. It lands on the roof of a building at a point displaced 24 m horizontally from the throwing point. How high above the throwing point is the roof?

Answer 1

Initial speed , Vo = 20mls Vox = Vo coso Voy - Vosine Xo = 24m les time taken to reach the roof - to to = Vox to y to - 24 to - 24 - = 7.50 see] 20005(37) Vocoso 24 = 1.50 see yo = voyt - Ig to - Vosno to- £g to - 20 sin(37) +1.50 et 89.8+(1.5) = to = 7.03m) & Height of roof from throwing point