Question

Unpolarized light is passed through an optical filter that is oriented in the vertical direction.

1) If the incident intensity of the light is 62 W/m22, what is the intensity of the light that emerges from the filter? (Express your answer to two significant figures.)

Answer 1

here,

the initial intensity of unpolarized light , I0 = 62 W/m^2

when an unpolarized light passes through a polarizer

the intensity of light passed is half of the initial intensity of light

so, the intensity of light passed , I = I0 * 0.5

I = 0.5 * 62 W/m^2

I = 31 W/m^2