Question

1. The Patient Protection and Affordable Care Act (PPACA), commonly known as just Affordable Care Act, attempts to reduce the total cost of healthcare in the US while improving the treatment effectiveness. A number of aspects of the law have been in effect for several years by now. In order to evaluate the performance of the US hospitals both before and after the implementation of the law, data was collected from a number of hospitals in the states of New York and New Jersey from time periods before and after the implementation of the law. This data is posted as an Excel file on Canvas. You can use Excel or r instead of a simple calculator to perform the arithmetic calculations faster, if you prefer. a. The mean readmission rate in the entire US was found to be 0.2200 before the law came into effect. Can the data from these two states be used to conclude that the readmission rate for NY and NJ hospitals is different from the overall US hospital population? Analyze the data for the two states separately. State your hypotheses and list any necessary assumptions clearly. Calculate the appropriate test statistic, report the p-value and give your conclusion based on a 5% significance level b. Repeat part (a), but use the data from the entire NY-NJ region together. Be sure to list the assumptions again, checking if any of the assumptions are different from those made in part Is there a difference in cost per stay between NY and NJ hospitals? State your hypotheses, Il necessary assumptions, calculate the appropriate test statistic, report your p-value, c. and give your conclusion based on a 10% significance level. d. Can you conclude that the mean cost per stay in the NY-NJ region as a whole decreased after the law was enacted? State your hypotheses, clearly list any necessary assumptions, calculate the appropriate test statistic, report the p-value, and give your conclusions based on a 10% significance level.

temperature	gender	hr
96.3	1	70
96.7	1	71
96.9	1	74
97	1	80
97.1	1	73
97.1	1	75
97.1	1	82
97.2	1	64
97.3	1	69
97.4	1	70
97.4	1	68
97.4	1	72
97.4	1	78
97.5	1	70
97.5	1	75
97.6	1	74
97.6	1	69
97.6	1	73
97.7	1	77
97.8	1	58
97.8	1	73
97.8	1	65
97.8	1	74
97.9	1	76
97.9	1	72
98	1	78
98	1	71
98	1	74
98	1	67
98	1	64
98	1	78

Answer 1

CD) a) Standand devialion of Pfulatfon atton fs not khence we have to pegform est One -Sample T. Readmtssion Rate N Descsiplive statistics Maan |.stDev | SEMeon |95%cRotu C-2024) Test Null hypothesis Altesmatfive lhypothests ア-value ?-value. 298 Stnce P-value ts less than alpha we 9eject null hų that the ms sron sate ts dtffsen thes aund e Conclude o.220o fos NY

one Sample T: ReadmisSton Rate i Menn | Strev | SEMe n |QSet.ct for μ 26 o-31o3) μ : Mean of Readmisson Rate NTI Test Null Altesmative hpes T-Value Pvalue O 021 nult hypothesns and we condude that the o. 2200- NT.

non ence oe ve to eron -test. one Sample T : Ransmission Rate both Descplive Stailisttcs 3s Test Altesnaive hypothests T-value p-value o.Qo o.3a6 Since p-value is more thalne a Seject null hyrothess and oe conclude O.22oo Cenid es bolh NI ord N

Method M2: mean of cost Rey stouNT Evatance ae not asumdfoy this analysts Descofptive StatiSties Samee | 2UD_ | 1652 | 551 Cost Diffegence -562

Test arf hyrotheses T-valueoF o.6 2 Since n-values more than alpha and Conclude that the cost ei stay between Nf and N not diffei.