Question

The first eight ionization energies of a third row element are 999.6, 2252, 3357, 4556, 7004, 8496, 27107, and 31719 kJ/mol. Identify the element.

Choose one:A. AlB. SC. MgD. PE. NaF. ArG. ClH. Si

Answer 1

Please refer below image it will help you;

First eight ionisation energies given as, 999.6, 2252, 3357, 4556, 7004,8496, 27107, 31719 ist and ard th th with wrth with So, If we look at the difference in the ionisation energies we came to know that, there is very large difforence in ionisation energy of 7 & 6 ionisation enorgy, It is almost triplod. So, that means, when we remove 6 h elecbon compound becomes stable, it has all the fulfilled electrons in shell So, to remove 7th electron it require more energy, so, compound has 6 octor most electrons in its shell It is salpher (s) option B S [NO] 35² 3p4 If we remove 6e S [NO] 35 3po stable