11 centimeters = 0.11 meters
r=0.11/2 = 0.055m
E=K*2*q / r^2
336 = K*2*q / r^2
q = 336*r^2/2k
q=336*(0.055)^2/(2*9*10^9)
= 5.65 *10^-11 C
An object of height 2.90 cm is placed 11.0 cm from a diverging lens of focallength magnitude 11.0 cm. Find the height of the image. 3. 145 b. -1.45 cm c. +3.22 cm d. +1.76 cm e. -2.82 cm
A diverging lens (f1 = −11.0 cm) is located 51.0 cm to the left of a converging lens (f2 = 30.5 cm). A 2.5-cm-tall object stands to the left of the diverging lens, exactly at its focal point. Determine the distance of the final image relative to the converging lens.
A diverging lens (f1 = −11.0 cm) is located 20.0 cm to the left of a converging lens (f2 = 32.5 cm). A 4.0-cm-tall object stands to the left of the diverging lens, exactly at its focal point. What is the height of the final image (including proper algebraic sign)?
A diverging lens (f1 = −11.0 cm) is located 22.0 cm to the left of a converging lens (f2 = 30.0 cm). A 2.5-cm-tall object stands to the left of the diverging lens, exactly at its focal point. What is the height of the final image (including proper algebraic sign)?
A converging lens (f = 11.0 cm) is held 5.90 cm in front of a newspaper, the print size of which has a height of 2.00 mm. Find (a) the image distance (in cm) and (b) the height (in mm) of the magnified print.
A diverging lens (f = –11.0 cm) is located 23.0 cm to the left of a converging lens (f = 34.0 cm). A 2.50-cm-tall object stands to the left of the diverging lens, exactly at its focal point. (a) Determine the distance of the final image relative to the converging lens. (b) What is the height of the final image (including the proper algebraic sign)?
. A diverging lens (f = –11.0 cm) is located 19.0 cm to the left of a converging lens (f = 30.0 cm). A 2.90-cm-tall object stands to the left of the diverging lens, exactly at its focal point. (a) Determine the distance of the final image relative to the converging lens. (b) What is the height of the final image (including the proper algebraic sign)?
An object is placed 11.0 cm in front of a concave mirror whose focal length is 24.0 cm. The object is 2.60 cm tall. What is the height of the image? (cm)
An object is placed 11.0 cm in front of a concave mirror whose focal length is 19.0 cm. The object is 3.10 cm tall. What is the height of the image?
Review Part A A 10-cm-long thin glass rod uniformly charged to 11.0 nC and a 10-cm-long thin plastic rod uniformly charged to 11.0 nC are placed side by side, 4.20 cm apart. What is the electric field strength 2.90 cm from the glass rod along the line connecting the midpoints of the two rods? The electric field strength is N/C Submit X Incorrect; Try Again; 5 attempts remaining