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Question 9 of 22> Attempt 1 Cheetahs can accelerate to a speed of 21.6 m/s in 2.45 s and can continue to accelerate to reach a top speed of 27.3 m/s. Assume the acceleration is constant until the top speed is reached and is zero thereafter. Let the +x direction point in the direction the cheetah runs. Express the cheetahs top speed uop in miles per hour (mi/h). hop61.08 mi/h Starting from a crouched position, how much time faccel does it take a cheetah to reach its top speed and what distance d does it travel in that time? accel- 8.816 d 2.45 If a cheetah sees a rabbit 116.0 m away, how much time toas will it take to reach the rabbit, assuming the rabbit does not move and the cheetah starts from rest? total26.46
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Answer #1

Given data The top speed of cheetah is, 1S v-27.3 m/s (27 lus)( 1609.3-lem )( 3600 s ) -(27.3m/s 1609.34 m lhr - 61.08 mi/h The time is t 2.45 s So, the acceleration is, 21.6 2.45 - 8.82 m/s2 Therefore, the total time is, 27.3 8.82 -3.09 s The total distance is, (8.82)(3.09) - 42.1 m For this 2(116) 8.82 5.13 s

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