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Problem 1.12. Let S21-{1, 2, 3, 4, 5, 6} and Op-{H. Т). Let X : 210,1 and Y 22 -» f0,1} be such that X(1)- X(3)-X(5)- 0. X(2) = X(4) = X(6) = 1, y(T) = 0, and y(H) = 1. Let P be the probability measure on 21 such that P ()1/15, P 2 2/15, probability measure on 22 with P2(T 1/3 and P2(H) 2/3. Prove that the distribution of X under P is the same as the distribution of Y under No. This says that if you are to only observe the outcomes of X and y, then there is no statistical test that can tell the difference between the two.

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