Question

Two masses (marbles, clay, or kittens, whichever) 18 kg and 29 kg collide while traveling toward each other at 6 m/s each. If collision were elastic, the total kinetic energy before and after the collision would be the same. Compare the total kinetic energy before and after the collision if it were completely inelastic instead. How much is lost?

Answer 1

- het, for inelastic collision the two masses sticks & have a velocity vi according momentum Conservation - mir - ma v = (m, rm2) vi (taking & k axis positive) (m. - ma) (m. + 2) (kinetic energy before collision- kinetic energy after collison) mirt & mart - 1 cm, + m2) v 2 (m. - mat 2 => (m+ m.) w2-(m4mm) mit " (mitm) => 4 m, ma cm,+ m2 x-emitma) Energy loss - Am, ma 7 cm, + m2) .

Here in Question, m, a 18kg Mer 29 kg V2 6 m/s & Energy loss ve 4 m, mer mitm2) (6) X, 4 x 18 x 29 2 (18+29) 2) 7 99.6 J