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A torque-angle diagram for a single cylinder four stroke engine is shown below. Please note the diagram is not to scale.

Torque Angle

The energy dissipated for each part of the cycle is as follows: Exhaust – 100j Induction – 130j Compression – 200j Ignition – 430j A Flywheel of radius of gyration 0.5m is to be used to ensure that the speed remains between 1500 & 2000 RPM. a) Determine the greatest fluctuation in energy. b) Determine the coefficient of fluctuation of speed and hence the required moment of inertia of the flywheel. c) Determine the required mass of the flywheel.

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Answer #1

Tonque gmitian 3 4R 2A A E exhaust C. gnduckin Compress ion EA E EB E 13 E 33 o E- 130- 2od E c = E +100 Ect 430 ED = ilEe E a)Emax E 100 Emin= E-330 Emin Emax E 1o0- E+ 33 43 J This is maximum Flctuation Coefficient oFbuckuatian o speed Wmax wm2 7X2000 2 XI50D wmean 6 0 60 2 183.1 s A E Twnea Omean 43 o O 286 (103-17)2 m2 I momen o Inerta This 2 I MK K=0.5 m Mx0.5- O

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