Average Kinetic energy
K=(3/2)kBT
4.36*10-21 = (3/2)*(1.38*10-23)*T
T=210.628 K
1 atm =1.01325*105 pa
From Ideal gas law
PV=nRT
=>n=PV/RT =(1.95*1.01325*105)(1.26*10-2)/(8.314)(210.628)
n=1.4217 moles
Notes Ask Your Teacher ถ7.69 points 1 Previous Answers KatzPSE 1 20 p059 The average kinetic...
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The average kinetic energy of an argon atom in a spherical container filled with argon gas and with a volume of 1.42 x 10-2 m3 is 4.40 x 10-21 ). If the pressure inside the container is 2.40 atm, how many moles of argon are in the container? moles
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My Notes Ask Your...
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