Question

During the annual egg-drop contest held from the top of the physics bullding, one brash young physics student throws a packaged egg up Into the alr from just over the edge of the building, such that the package, on its way down, just misses the edgeof the building and falls to the ground below. The building is 58 m high and the package is in the air for ss. (a) Find the maximum height h above the top of the building that the egg package attains. 10.72 Your response differs from the correct answer by more than 10%. Double check your calculations. m (b) What is the magnitude of the velocity of the egg package just before It hits the ground? 34.5 Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error. m/s

Answer 1

Let initial velocity is 4 at point 0 for motion form O to A initial velocity is (u) = u final velocity v_1 = 0 (for maximum height) acceleration a = -g v_1 = u_1 + at_1 o = u_1 - gt_1 t1 = u/g v^2_1 = u^2_1 + 2a_l h_l o = u^2 - 2gh max hmax = 42/2g formation A to B initial velocity u_2 = 0 finial velocity I v_2 a_2 = g R_2 = H + h_max using H_2 = ut_2 + 1/2 a_2 t^2_2 H + hmax = 0 + 1/2 g t^2_2 squareroot 2(H + hmax/g) = t_2 g = 9.8 m/s^2 \r\n t1 + t2 = 5 sec u/g + squareroot 2(H + hmax/g = 5 2(h + hmax/g) = (5 - 4/g)^2 2H/g + 2hmax/g = (5 - 4/g)^2 2H/g + 2u^2/2g^2 = 25 + u^2/g^2 - 10^4/g 2H/g = 25 - 104/g 104/g = 25 - 2H/g = 25g - 2H/g 10u = 25 times 9.8 - 2 times 58 10 u = 245 - 116 = 129