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Items are inspected for flaws by two quality inspectors. If a flaw is present, it will be detected by the first inspector with probability 0.92, and by the second inspector with probability 0.7. Assume the inspectors function independently Assume that the second inspector examines only those items that have been passed by the first inspector. If an item has a flaw, what is the probability that the second inspector will find it? Round the answer to three decimal places A system consists of four components, connected as shown in the diagram. Suppose that the components function independently, and that the probabilities of failure are 0.05 for A 0.03 for B, 0.09 for C, and 0.11 for D. Find the probability that the system functions. B A population of 600 semiconductor wafers contains wafers from three lots. The wafers are categorized by lot and by whether they conform to a thickness specification. The following table presents the number of wafers in each category. A wafer is chosen at random from the population Lot Conforming Nonconforming A 88 20 157 35 260 C 40 References eBook & Resources Section Break Difficulty: Medium Chapter: 02 Probability Section: 02.03 Conditional Probability and Independence 19 value Required information 10.00 points If the wafer is conforming, what is the probability that it is not from Lot C? A population of 600 semiconductor wafers contains wafers from three lots. The wafers are categorized by lot and by whether they conform to a thickness specification. The following table presents the number of wafers in each category. A wafer is chosen at random from the population. Conforming Nonconforming 20 Lot A 88 B 157 35 C 260 40 eBook & Resources References Section Break Difficulty: Medium Chapter: 02 Probability Section: 02.03 Conditional Probability and Independence 20. value Required information 10.00 points If the wafer is not from Lot C, what is the probability that it is conforming? 히비히

Answer 1

1. Second Inspector will detect it only if the first inspector misses

P = P(first misses)*P(second detect)

P = 0.08*0.7 = 0.056