Question

PART 2: Covalent Bonds 6. Draw a reasonable Lewis Structure for the following compounds: H3B03 CH3NO2 Ö - 14 B CaHPO4 PC13F2 Se F6 XeFg 7. For each of the molecules in problem 6, assign the formal charge of each atom 8. For each of the molecules in problem 6, assign the bond order to each bond 9. Are any of the bonds in the molecules in problem 6 lonic or are all covalent bonds Page 4 of 7

Answer 1

Lewis Structure of CH₃NO₂

I- 7-O H- Ć - 0: U- CH₃ NO2

Lewis Structure of CaHPO₄

0-р — о Cat* О Ca HPO4

Lewis Structure of PCl₃F₂

CI-P I-7-7: Pcl₃F2 &

Lewis Structure of SeF₆

Eife: :fe: Sefb

Lewis Structure of XeF₆

Formula for Formal Charge = no. of free valence electrons in a neutral atom - 1/2 [ no. of bonding electrons ] - [no.of non bonding electrons]

Formal Charge of each atom in CH₃NO₂

For Hydrogen atom the formal charge = 1 - 1 - 0

= 0

For Carbon atom the formal charge = 4 - 8/2 - 0

= 4 - 4 - 0

= 0

For Nitrogen atom the formal charge = 5 - 4 - 0

= 1

For Oxygen atom the formal charge = 6 - 1 - 6

= -1

For Oxygen atom connected with double bond the formal charge will be = 6 - 2 - 4

= 0

The Overall charge for the CH₃NO₂ will be 0

Overall charge for CaHPO₄ is 0

Overall Charge for SeF₆ is 0

Overall charge for XeF6 is 0

Ionic and Covalent Bonds in CH₃NO₂

Though it has 5 valence electrons, 3 bonds are utilised in forming covalent bond with C atom, likewise 2 covalent bonds with O atom. The Nitrogen atom with two unshared electrons is hard to left.

CaHPO₄ is an ionic Compound

SeF₆ is a Covalent Compound

XeF₆ is a covalent compound