Problem 6: A uniform beam of length L = 3.2 m and mass M = 32 kg has its lower end fixed to pivot at a point P on the floor, making an angle θ = 29° as shown in the digram. A horizontal cable is attached at its upper end B to a point A on a wall. A box of the same mass Mas the beam is suspended from a rope that is attached to the beam one-fourth L from its upper end.

Part (a) What is the y-component Py of the force, in newtons, exerted by the pivot on the beam?
Part (b) Write an expression for the tension Tin the horizontal cable AB
Part (c) What is the x-component P of the force, in newtons, exerted by the pivot on the beam?
C)
Tension, T = 5 mg cot(theta)/4
T = 5 x 32 x 9.8 x cot(29)/4
T = 707.19 N
Comment in case any doubt please rate my answer....
Problem 6: A uniform beam of length L = 3.2 m and mass M = 32 kg has its lower end fixed to pivot at a point P on the floor
b Write an expression for the
tension T in the horizontal cable AB
25%
Part (c) Write an expression for the x-component
Px of the force exerted by the pivot on the
beam, in terms of T.
25%
Part (d) What is the tension in the horizontal cable, in
newtons, if the mass of the beam is 34 kg, the length of the beam
is 11 m, and the angle is 28°?
A uniform beam of length L
and mass...
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