Question

37. The following curve may correspond to the titration of Hd 5 20 25 10 15 0.080 M NaOH volume, mL (a) 5.00 mL of a 0.080 M diprotic acid, H,A (b) 5.00 mL of a mixture consisting of 0.080 M H A and 0.080 M HA (c) 5.00 mL of a mixture consisting of two acids with the same K. 0.080 M HA, and 0.16 M HB (d) 5.00 mL of a mixture consisting of two acids with the same concentration (0.080 M), but different K

How do I know the answer is B?

Answer 1

31 13th Week 090-275 Saturday 14 2nd 12 4 equna lence pain 2 1 10 15 20 O.0%0 MNao 14 volums 25 01 Sunday

For the general case of H_{​​​​​​2}​​​​​A titrated with NaOH, the neutralisation reaction could be written as :

H_{​​​​​​2}​​​​​A + 2 NaOH = Na_{​​​​​2} A + 2 H_{​​​​​​2} O

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