Is the following statement true or false, why? 1. Let m[1]...m[p] be the LCS of A[1]...A[i]...
Is the following statement true or false, why?
1. Let m[1]...m[p] be the LCS of A[1]...A[i] and B[1]..B[j]. If A[i] is not equal to B[j], is m[1]...m[p-1] a common subsequence of A[1]...A[i-1] and B[1]...B[j-1]?
2. Let m[1]...m[p] be the LCS of A[1]...A[i] and B[1]..B[j]. If A[i] is not equal to B[j], is m[1]...m[p-1] a longest common subsequence of A[1]...A[i-1] and B[1]...B[j-1]?
Homework Answers
1. True
Explanation: If A[i] != B[j], this means that the common subsequence must lie before indices i and j.
Hence, m[1]...m[p-1] a common subsequence of A[1]...A[i-1] and B[1]...B[j-1].
2. False
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Is the following statement true or false, why? 1. Let m[1]...m[p] be the LCS of A[1]...A[i]...
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