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50. In the reaction below, how many molecules of hydrogen are required to react with 9.79 g of nitrogen? 3H2(g) + N2(g) → 2NH
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Answer #1

Moles of N2 = mass / molar mass

= 9.79 / 28

= 0.35

Moles of H2 = 3* moles of N2

= 3*0.35

= 1.05

Number of molecules = avagadro number * moles

= 6.022*10^23 * 1.05

= 6.32*10^23 molecules

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