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A 5.5 g dart is fired into a block of wood with a mass of 22.6...

A 5.5 g dart is fired into a block of wood with a mass of 22.6 g. The wood block is initially at rest on a 1.5 m tall post. After the collision, the wood block and dark land 2.5 m away from the base of the post. Find the initial speed of the dart.
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Answer #1
mu = (m+M)v

speed = v = 0.1957u

Now,
1.5 = 0.5gt^2
time = t = 0.553 seconds

2.5 = v x 0.553
speed = v = 4.518 m/s

SPeed = u = 23.088 m/s
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