Question

When you start your stopwatch, a particle moving on the x-axis is observed somewhere between the positions x = 10 m and x Sometime during the fourth second, it passes the position x 22 m and at the instant t = 12 s it is observed somewhere between the positions x 55 m and x 60 m. When do you expect its arrival at the position x = 88 m? 12 m

Answer 1

Suppose th pantde wan at x-10 m And Then YLA ched 2.2 m S0 te diston ca trawaged 12 m it teok in behwaun 3 to 4 Aecs. max. velou m/s 4m/s Similanly to a minim um t needs to tanh 6am 12 m. and it takes 4 ee to Yea ch x22 m vele ditg minimum 22-12 : 2.5 m/s. 4 N, it I panti ches moven with wni for m Her in 12s it cam go (with velo ci) (with minimum velo ct max 30 with minimum peed t camt reach minimum paed is in So the 12 sec- not feambue Apeed is tearibu. But max imit trr minimum speed tthe Clewated an tollews can be minm Passible dis tom ce traversed is : (-12) m 43m tthe in 12s 43 m/s3.583 veladl minimum take to rach 88m Hance, the marimum time it Ss-88 9.21 5ce t 3.583 is 1 talee is mimmum time it may the 7 sec 4 88m panticla ruachs Hence In tha tinme intervl batween t- (12+1) s 19 sac to t"(12+9.2)5 21.2sec