Question

A small ball rolls horizontally off the edge of a tabletop that is1.17 m high. It strikes the floor at a point 1.18 m horizontallyaway from the edge of the table. (a) How long is the ball in theair? (b) What is its speed at the instant it leaves thetable?

Answer 1

Kinematics:
Y = y_o + v_yot +(1/2)a_yt²

0 = (1.17m) + 0t +(1/2)(-9.81m/s²)t²

t² = (-1.17m)/(-4.91m/s²)

t² = 0.238 s²

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t = 0.488s

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X = x_o + v_xot +(1/2)a_xt²

1.18m = 0m + v_xo(0.488s) + 0t²

v_xo = (1.18m)/(0.488s)

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v_xo = 2.42 m/s

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I hope this solution was a Lightsaber for you.

Please remember to always be a Physics Jedi.