Question

Java:

can also use “if else” statements

Write a program that can convert an integer between 0 and 15 into hex number (including 0 and 15). The user enters an integer from the console and the program displays the corresponding hex number. If the user enters an integer out of range, the program displays a warning message about the invalid input.

Table. Conversion between Decimal and Hexadecimal

Decimal	Hexadecimal
0	0
1	1
2	2
3	3
4	4
5	5
6	6
7	7
8	8
9	9
10	A
11	B
12	C
13	D
14	E
15	F

Answer 1

import java.util.Scanner;

public class Tester3 {

   public static void main(String[] args) {

         Scanner sc = new Scanner(System.in);

         System.out.print("Please Enter an Integer between 0 to 15 : ");

         int input = sc.nextInt();

         if(input >= 0 && input <= 15){

            switch(input){

                  case 10 :

                  System.out.println(input+"----> A ");

                  break;

                  case 11:

                  System.out.println(input+"----> B ");

                  break;

                  case 12 :

                  System.out.println(input+"----> C ");

                  break;

                  case 13 :

                  System.out.println(input+"----> D ");

                  break;

                  case 14 :

                  System.out.println(input+"----> E ");

                  break;

                  case 15 :

                  System.out.println(input+"----> F ");

                  break;

           

                  default :

                  System.out.println(input+"----> "+input);

                  break;

                  }

            }

         else{

               System.out.println("\nInvalid Input..please Try Again ");

               System.out.println("Program Exiting.......");

         }

   }

}

Output:

Please Enter an Integer between 0 to 15 11 11--1 --->B

lease Enter an Integer between 0 to 15 16 Invalid Input..please Try Again Program Exiting.