What capacitance is required to store an energy of 7.9kW·h at a potential difference of 1100...
Homework Answers
Potential difference, V = 1100 V
Now, Energy stored in capacitor, E = (1/2)CV2,
which gives, 2.844x107 = (1/2)*C*(1100)2, andwe get, C = 47.01 Farad
W=1/2CV2
C=2W/V2
=2*2.84x107/11002
=47.01 F
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