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e 3.27 The distribution of detectable flaw sizes in tubing is given by Eq. 3.88 with e 1/17 cm. There are an average of three detectable flaws per centimeter of tubing. (a) What fraction of the flaws will have a size larger than 0.8 cm? (b) What is the probability of finding a flaw larger than 0.8 cm in a 100-m length of tubing? (c) In 1000 meters of tubing?
al distribution. 1he CDF IS (x) 1 e-x/e = - DF is
math   Statistics-And-Probability   
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Answer #1

Here we are going to formulate the problem in terms of probability distribution by defining a random variable "X" .

ans ά, xle a mandom vrìnhke uiten denotes the size et a deteetabk Nou, we want to know tu tractisn eh tu 知.langcn than .. 0. 8 em. ,le, Harnbaku. 아 a debetablL +has wis. Size So 1- F (o-s) -(0.8x17) neling a enthan D.8em . Noe are aordem somple we ane interarted n a faus whic than 0 8 em 8 ) 3xto4 induperdent3 x lo4 (8x7 1 0.9635 0.0365 So than 0.8 a.m. l>n a 100 meen tubi s . 0 365 aJeeo meter tubin we wil have x/0 lntott (3 x 1o5) So 0.8 wuo varioble deotn the Size n 5 xib -(0.8x17) than 0 3 cm talrs place wth probabuu amesk eal to

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