Question

1

slli x30, x5, 3

add x30, x10, x30

slli x31, x6, 3

add x31, x11, x31

ld x5, 0(x30)

addi x12, x30, 8

ld x30, 0(x12)

add x30, x30, x5

sd x30, 0(x31)

// x30 = f*8

// x30 = &A[f]

// x31 = g*8

// x31 = &B[g]

// f = A[f]

For the RISC-V assembly instructions below, what is the corresponding C statement? Assume that the variables f, g, h, i, and j are assigned to registers x5, x6, x7, x28, and x29, respectively. Assume that the base address of the arrays A and B are in registers x10 and x11, respectively.

Answer 1

7.3の= add x 3) , xil, x31 ニValue of(x30) addi Xi2 X 1 2 add x30, x30, xS メ30 = x30 +XS store value of x 30 + A

CODE :

main.c saved 1 #include 3 int main(void) 4. int f,g; //Initialize elements of array A,B 6 7int A -5,7,11,20,40,15,100,300, -25,66; 8 int B[ 10,1,2,3,4,5,6,7,-8,9}; 10 12 14 //Initialize f and g int i- f; //x30 17 B[g]-1; 18 19 /Testing 20 21 | printf("B[g] printf("f-%d\n",f); %d " , B[g]); - 23 24 25 return 0;

#include

int main(void)

{

int f,g;

//Initialize elements of array A,B

int A[] = {5,7,11,20,40,15,100,300,-25,66};

int B[] = {0,1,2,3,4,5,6,7,-8,9};

//Initialize f and g

f = 3;

g = 6;

int i = f; //x30

f = A[f];q

i = A[i+1] + f;

B[g] = i;

//Testing

printf("f = %d\n",f);

printf("B[g] = %d",B[g]);

return 0;

}

OUTPUT :

gcc version 4.6.3