Question

Molarity(m)=Moles (mol) of solute/Liters (L) of solution

Molarity of standard NaOH from bottle = 0.1005 M

Molarity of NaOH added in titration (mL) = 10.47 mL

1. Moles of NaOH added in titration ______

Answer 1

Molarity(M)=Moles (mol) of solute/Liters (L)

It is the formula

We are given with

Molarity = 01005 M

Volume = 10.47 mL

Converting mL to L

$10.47 mL\times \frac{1 L}{1000 mL}$

=0.01047 L

Volume = 0.01047 L

Plug in the values in the formula

$Molarity=\frac{mol}{volume in L}$

$0.1005 M=\frac{mol}{0.01045 L}$

Multiply both sides with 0.01045 L

$0.1005 \times 0.01045=\frac{mol}{0.01045}\times 0.01045$

0.001050 = mol

Therefore, moles of NaOH in solution = 0.001050 mol = 1.050 x 10^-3 mol