Question

Using python, write code for problem. Please also put screenshot of your code.

The following program will perform properly if the user enters 0 in response to the request for input. However, the program will crash if the user responds with "eight". Rewrite the program using a try/except statement so that it will handle both types of responses. See Fig. 6.1. while True: n = int (input ("Enter a nonzero integer: ")) if n! = 0: reciprocal = 1/n print ("The reciprocal of {0} is (1:, 3f)". format (n, reciprocal)) break else: print ("You entered zero. ") Enter a nonzero integer: 0 You entered zero. Enter a nonzero integer: eight You did not enter a nonzero integer. Enter a nonzero integer: 8 The reciprocal of 8 is 0.125

Answer 1

# Stop break #Otherwise else: &Display message print("You entered zero. Try again.") Sample output Python 3.4.3 Shell File Edit Shell Debug Options Window Help Python 3.4.3 (v3.4.3:9b73f1c3e60, Feb 24 2015, 22:43:06) [MSC v.1600 32 bit (In tel) on win32 Type "copyright", "credits" or "license)" for more information RESTART Enter a nonzero integer: 0 You entered zero. Try again. Enter a nonzero integer: eight You did not enter a nonzero integer. Try again. Enter a nonzero integer: 8 The reciprocal of 8 is 0.125 Ln:11 Col: 4

Executable code

#Loop
while True:
   
    #Prompt the user for input
    n = input("Enter a nonzero integer: ")
   
    #Try block
    try:
      
        #Integer
        n = int(n)
   
    #Exception
    except ValueError:
      
        #Print exception
        print("You did not enter a nonzero integer. Try again.")
      
        #Continue to get user input
        continue
   
    #Check condition
    if ( n != 0 ):
       
        #Find reciprocal
        reciprocal = 1/n
       
        #Display reciprocal
        print ("The reciprocal of {0} is {1: .3f}".format (n, reciprocal))
       
        #Stop
        break
   
    #Otherwise
    else:
       
        #Display message
        print("You entered zero. Try again.")