Question

note: the data doesnt have to come from statcrunch, it can be from a random data or source or whatever, nothing specific. it can be on body temperature of people who smoke and who dont smoke (if possible I prefer data on that). and i need is just one data graph or chart (histogram or box plot). everything else is self explanitory.

thanks

1) Select a data source to analyze in Staterunch (Select Explore; Data) -Specify one research question your group would like to address with this data source. -Using Statcrunch, construct one or more graphs (e.g, histogram or box plot) and calculate some descriptive statistics (e.g., mean, variance, standard deviation, skew, etc.) that will help provide some initial infomation regarding your research questions. Develop a hypothesis test that would be amenable to a one sample t test. What are the results of your test in the context of the problem? What are some research questions that you cannot address from the available data? Paragr 1) Description of the research question you addressed in part 1 2) Graphs and descriptive statistics 3) Results in the context of the problem 4) Description of the research article you found and how this article's findings relate to yours 5) Limitations of the work you conducted 6) Reference of your article

Answer 1

Terminalx Console length(mtcarsShp) #hp of 32 cars is the default dataset in R here [1] 32 >mtcars$hp # 32 data points of hp of 32 cars here [11 110 110 > 93 110 175 105 245 62 95 123 123 180 180 180 205 215 230 66 52 65 97 150 150 245 175 66 91 113 264 175 335 109 HP-mtcars $hp #stored data of 32 car's HP in a variable named HP mean(HP) [1] 146. 6875 median(HP) [1] 123 sd(HP) [1] 68. 56287 boxplot (HP) #Plotted box plot here of HP hist (HP) #Now for hypothesis testing > #1et's create a > #Null Hypothesis: Mean HP of the cars is =150 #alternative Hypothesis: Mean HP of the cars is / = 150 #Performingt test below to check the hypothesis > t.test (HP, mu > hypothesis > > 0) = One Sample t-test data: HP t 12.103, df= 31, p-value alternative hypothesis: true mean is not equal to 0 95 percent confidence interval: = 2.794e-13 121.9679 171,4071 sample estimates: mean of x 146. 6875 #since p value of the test is 2.794 10A-13 which is very very less than 0.05 we have to hence here we can say that the mean HP of the cars of this sample is not 150HP #The reasear ch question 1ike if all the cars have HP ysis reject Ho and > capacity of 150 can be verified by the above anal >

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Histogram of HP 50 100 150 200 250 300 350 HP Frequency 7

From the above histogram of the data we can say that the data is right/positively skewed. The above analysis is done in R. You can use any tool to do the same.

Hope the above answer has helped you in understanding the problem. Please upvote the ans if it has really helped you. Good Luck!!