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A current loop in a motor has an area of 0.85 cm2. It carries a 240...

A current loop in a motor has an area of 0.85 cm2. It carries a 240 mA current in a uniform field of 0.62 T .

What is the magnitude of the maximum torque on the current loop?

Express your answer using two significant figures.
τ = __________N*m


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Answer #1
Concepts and reason

The concepts used to solve this problem are torque acting on a current carrying loop.

Initially, use the expression of torque acting on loop in a magnetic field. Find the condition for maximum value of torque. Substitute the values in the expression and find the maximum torque acting on the current loop.

Fundamentals

The expression of torque on a current carrying loop can be given as follows:

= BIAsin

Here, B is the magnetic field, I is the flowing current, A is the area of loop and is the angle between perpendicular distance and F.

Substitute 90 for in the expression = BIAsin .

7 BIAsin 90° = BIA

Substitute 240 mA for I, 0.62 T for B and 0.85 cm 2 for A in equation T BIA .

10 m2 0.85 cm1.0 cm 103 A r =(0.62 T) 240 mA10 mA 2 126x10 N m 1.3x10 N m

Ans:

The torque acting on current loop is -5 1.3x10 N m .

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