Answer:
Given,
To determine the number of moles of potassium
Let us consider,
k = 0.693 / t1/2
k = 0.693 / 1.3 x 10^9
k = 5.33 x 10^-10 yr-1
t = 1.3 × 10^9
k = 1/t * ln (Ao / At)
substitute the known values in above expression
5.33 x 10^-10 = 1/ 1.3 x 10^9 * ln (1.20 x10^-7 / At)
0.693 = ln (1.20 x10^-7 / At)
At = 6*10^-8 mol
moles of potassium K-40 remainded is 6 x 10^-8 mol
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No.10 , write the steps clearly
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please the hole steps
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