Question

S1 2. Find the angle through which the smaller pulley turns as the 10-inch pulley makes one revolution. State the answer in radians and degrees. Assume the belt does not slip on the pulleys. in. s2 02 6i rad deg rees

Answer 1

"R_1 = 10 inch circumference of 10 inch pulley S = 2 pi r_1 = 2 pi (10 inch) circumference of smaller pulley s' = 2 pi r_2 = 2 pi (6 inch) Distance travel by 10 inch pulley in one complete rotation = Distance travel by 6 inch pulley s = s"" = n (s') no. of turns of 6 inch pulley n = s/s' = 2 pi (10 inch)/2 pi (6 inch) = 1.6666 Total angle travel by 6 inch pulley when 10 inch pulley makes one revolution theta_2 = (1.6666) (2 pi rad) (because Angle of one complete rotation = 2 pi rad) theta_2 = (1.6666) (2) (3.1415) rad = 10.471 rad (or) theta_2 = (1.66666) (360 degree) = 600 degree"