Question

Refer to the energy level diagram for the transitions of the hydrogen atom in your lab manual to answer the following:

What is the energy of the principal quantum number 3, in units of reciprocal centimetres, cm^-1?

What principal quantum number has an energy of -6855 cm^-1

Referring to the two values above, what amount of energy is given off when an atom transitions from the higher energy state to the lower energy state?

Answer 1

The negative sign indicates that this energy is released. So the amount of energy given off is 5338 cm-1.

ANSWER nith For energy H-atom, level is the given energy of by the electron in formula: TO En = – 109, 737. n2 where 109737 con = RH(Rydberg constant) n = principal quantum number. & i) Cuven n =3 , from the above formula (1) = - 109737 ml - Ez = -12 193 32 con ii) I Cuven energy = -6855 com'; equating this value to the above Formula (1) – 6855 con' =– 1096737 cm 22 Ok n² = 109737 6855 = 16.00 (n=4) in Hence, n=4 principal quantum number has - 6855 an energy. when the electron jumps from n=4 to non the amount of energy given off (DE) is DE = Efinal - Einitial = Ez-Ey = (-12193 -(-6855)) em = - 5338 con