The Moon has an average atmospheric pressure of 3 × 10-15atm.
Would it be easier or harder to drink from a straw on The Moon than on Earth?
Would it be easier or harder to drink from a straw on The Moon than on Earth?
| It would be harder. |
| It would be easier. |
| It would be the same as on Earth. |

The Moon has an average atmospheric pressure of 3 × 10-15atm. Would it be easier or...
Atmospheric Mass Venus and Earth have about the same mass and radius, but the atmospheric pressure on the surface of Venus is measured to be 90 times larger than the pressure at the surface of the Earth. (a) Assuming Venus' atmosphere is pure CO2 and Earth's atmosphere is pure N2, estimate the atmospheric scale height for each planet. For simplicity you can assume that both atmospheres are isothermal with T = 550 K for Venus and T = 250 K...
The average radius of the moon has been measured to be 1.74×106m and the value of surface gravity is 1.62m/s2 . 1) Mass of moon? M=____________kg 2) If the earth has a mass of 5.97×1024kg and the moon orbits at an average distance of 3.85×108m , what is the orbital period of the moon about the earth? T=____________days 3) What is the average gravitational force between the Earth and the Moon? F=_______N
A milkshake has viscosity of 0.40Pa⋅s . To drink this shake through a straw of diameter 0.56 cm and length 22 cm , you need to reduce the pressure at the top of the straw to less than atmospheric pressure. If you want to drain a 400mL shake in 1.0 minutes, what pressure difference is needed? You can ignore the height difference between the top and the bottom of the straw.
A
and B
Part A At the surface of Mars the atmosphere has average pressure 6.0 x 10' Pa and average temperature -63°C. What is the mean free path of atmospheric molecules (assumed to be spheres of radius 2.0 x 10m ) at the surface of Mars? Express your answer with the appropriate units. x = 468 K Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining Part B How many times greater is your answer in...
An undiscovered planet, many lightyears from Earth, has one moon in a periodic orbit. This moon takes 1710 * 10^3 seconds (about 2.0 * 10^1 days) on average to complete one nearly circular revolution around the unnamed planet. If the distance from the center of the moon to the surface of the planet is 295.0 * 10^6 m and the planet has a radius of 3.20 ^ 10^6 m, calculate the moon\'s radial acceleration.
A milkshake has viscosity of 0.60Pa⋅s. To drink this shake through a straw of diameter 0.56 cm and length 22 cm, you need to reduce the pressure at the top of the straw to less than atmospheric pressure. Part A If you want to drain a 560mL shake in 1.0 minutes, what pressure difference is needed? You can ignore the height difference between the top and the bottom of the straw.
An undiscovered planet, many lightyears from Earth, has one moon in a periodic orbit. This moon takes 23.0 days on average to complete one nearly circular revolution around the unnamed planet. If the distance from the center of the moon to the surface of the planet is 2.240× 10 5 km and the planet has a radius of 3.250× 10 3 km, calculate the moon's radial acceleration ?.
A Review | Constants Periodic Table A milkshake has viscosity of 0.40Pa.s. To drink this shake through a straw of diameter 0.56 cm and length 22 cm, you need to reduce the pressure at the top of the straw to less than atmospheric pressure If you want to drain a 500mL shake in 30 minutes, what pressure difference is needed? You can ignore the height difference between the top and the bottom of the straw.
An undiscovered planet, many lightyears from Earth, has one moon in a periodic orbit. This moon takes 2160 × 10^3 seconds (about 25 days) on average to complete one nearly circular revolution around the unnamed planet. If the distance from the center of the moon to the surface of the planet is 225.0 × 10^6 m and the planet has a radius of 3.80 × 10^6 m, calculate the moon's radial acceleration ?c .
An undiscovered planet, many lightyears from Earth, has one moon in a periodic orbit. This moon takes 1710× 10^3 seconds (about 2.0×10^1 days) on average to complete one nearly circular revolution around the unnamed planet. If the distance from the center of the moon to the surface of the planet is 265.0× 10^6 m and the planet has a radius of 3.10× 10^6 m, calculate the moon's radial acceleration ?c.