Question

Chapter 28, Problem 003 An electron that has a velocity with component 2.5 × 106 m s and y component 3 3 x 106 m s moves through a uniform magnetic e d it x component 123 and y component a 9 T. (a) Find the magnitude of the magnetic force on the electron. (b) Repeat your calculation for a proton having the same velocity. (a) Number (b) Number Units Units

Answer 1

28] a]

The magnetic force on the electron will be:

$\vec{F}=q \vec{v}\times \vec{B}$

$\vec{F}=-e(10^6)\begin{vmatrix} i&j&k\\ 2.5&3.3&0\\ 0.023&-0.19&0\\ \end{vmatrix} = - e(10^6)[-2.5(0.19)-3.3(0.023)]\hat{k}$

=> $\vec{F}= +\left( 8.814\times 10^{-14}N\right) \hat{k}$

the magnitude of the magnetic force is F = 8.814 x 10^-14 N

b] Since a proton and an electron have the same charge and the magnetic force is not dependent on the mass of the charge, therefore, the magnitude of charge will be the same.