59,231.41J of heat is added to 1000 g of ice at -10 oC. How much ice melts?
First the ice must wam to 0
Q = mc(delta T)
Q = (1)(2090)(10) = 20900
The heat left = 59231.41 - 20900 = 38331.41
Then Q = mH
38331.41 = m(3.3 X 105)
m = .116 kg (116 grams)
(This is done using the values from my book. If this is slightly off, comment below with values used by your book and a correct ion can be made)
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