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In Problem 27 of Exercises 4.9 you were asked to solve the following linear system dx1 1 dt 50 dx2 1 2 dt 50 75 dx3 1 2 x2 75

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YI -2X 75 2 2 23 2S ca) X (0) S 2(0)=10 3 0)= 5 2s A = Let O 2 .04 -O2- A-2I o =) o 2 -.04 -A (at.02)(A2) (2+04)- A4.08 .o 2= 15 et/50 5 e 2/75 (9 e150 - 7 = 5 et/25 (-14 e7512 e50 +3))3 4 187, 7 C 2 s 2 A3 So V3 ethn7 E/2s C1e - 3 4 : (}2 4 C3S C23 3 C1t2C2t 43 C2=-3S is e-so 4 se-Fls o 3 sE2/7s (H717 Ise-t

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