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Table I 25 tin seconds 5 10 15 20 30 35 40 45 v(t) in feet per second 274.27 179.23 80.80 56.68 35.91 18.04 2.65 223.19 141.4

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A. Given that -O.034 4G2 V(t1 1100 5 d t) instantaneous arceleation 1100 fo03) e 700111e-0 -0. 031 At 15Sec O03 q = t-15ser -0-031 e 100 B. 463 Dis placoment X()= VQ)dt -0 03+ X (1 1100 -0.03t - 1 LL00 0.03 -110000 0.034 0-0305) X t - 15 0.45 e -1386A t 4T sec - 1.35 -10000 463. X9 41 58 - 3, l68. 492 =,326. 492| 1326.491 tecet From 15s 40 25s P =13,649.087 +,326 492 6,322

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