A six sided die is rolled three times independently. How many different ways can you get a sum of 11? sum of 12?
A six sided die is rolled three times independently. How many different ways can you get...
A person rolls a standard six-sided die 12 times. In how many ways can he get 6 fours, 5 ones, and 1 two? PLEASE DO NOT ANSWER UNLESS YOU ARE CONFIDENT IT IS CORRECT.
A person rolls a standard six-sided die 9 times. In how many ways can he get 3 fives, 5 sixes, and 1 two?
A person rolls a standard six-sided die 8 times. In how many ways can he get 3 fives, 4 sixes, and 1 two?
If a coin is tossed 5 times, and then a standard six-sided die is rolled 4 times, and finally a group of two cards are drawn from a standard deck of 52 cards without replacement, how many different outcomes are possible?
If a coin is tossed 2 times, and then a standard six-sided die is rolled 2 times, and finally a group of two cards are drawn from a standard deck of 52 cards without replacement, how many different outcomes are possible?
If a coin is tossed 2 times, and then a standard six-sided die is rolled 3 times, and finally a group of four cards are drawn from a standard deck of 52 cards without replacement, how many different outcomes are possible?
If a coin is tossed 3 times, and then a standard six-sided die is rolled 4 times, and finally a group of four cards are drawn from a standard deck of 52 cards without replacement, how many different outcomes are possible?
A standard six sided die is rolled 11 times. What is the expected value of the number of times an odd number will be rolled. Do not round your answer.
Suppose I asked you to roll a fair six-sided die 6 times. You have already rolled the die for 5 times and six has not appeared ones. Assuming die rolls are independent, what is the probability that you would get a six in the next roll? 1/6 1/2 5/6 0 1
A fair 6-sided die is rolled three times. Which is more likely: a sum of 11 or a sum of 12? Answer the question by calculating the probabilities for both. Thint 1] There are multiple ways to solve this problem. You may list all the favorable permutations to get the sum. However, this might be tedious and more error-prone. An easier way is to list only the favorable combinations (i.e., 3 numbers regardless of their order), and then find out...