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Catch Julie throws a ball to her friend Sarah. The ball leaves Julies hand a distance 1.5 meters above the ground with an initial speed of 14 m/s at an angle 60 degrees; with respect to the horizontal. Sarah catches the ball 1.5 meters above the ground. 1) What is the horizontal component of the balls velocity when it leaves Julies hand? 7 /s Submit 2) What is the vertical component of the balls velocity when it leaves Julies hand? 12.12 s Submit 3) What is the maximum height the ball goes above the ground? Submit 4) What is the distance between the two girts? 17.3 Submit
5) After catching the ball, Sarah throws it back to Julie. The ball leaves Sarahs hand a distance 1.5 meters above the ground, and is moving with a speed of 8 m/s when it reaches a maximum height of 11 m above the ground. What is the speed of the ball when it leaves Sarahs hand? m/s Submit 6) How high above the ground will the ball be when it gets to Julie? (note, the ball may go over Julies head.) m Submit
Please help I can’t seem to get parts 3,5, or 6 correct!
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Answer #1

Concept: we use equation of kinematics for motion in two dimension under gravity for solution as shown below,

mum height above launch point for a Pny Povjech le manc 2g 7.5m w ener conservahonノ E aneat wax eig ht nerqy whe it leave Sarahs h h of 1i m mVi ナ H=11m component of velo f ba oSarah Saralh isCr (し of vel of ball X=dis tamu between giMs 8m/s)t = 17.3m reach Julie fom Sarah at that time 2. OY h 6.57 m height alove aroun H = ntLSw***************************************************************************************************
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