Question

about 2% of the population has a particular genetic mutation. 800 people are randomly selected

Answer 1

Solution:-

a) P(Atmost 3) = 0.01063538

P(female) = 0.50

n = 16

x = 3

By applying binomial distribution:-

P(x,n) = ⁿC_x*p^x*(1-p)^(n-x)

P(x < 3) = 0.01063538

b) No, this does not support a charge of gender discrimination.

Since the p-value(0.01063538) is greater than cut off value (0.005), hence this is not unusual event.

No, this does not support a charge of gender discrimination.